Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.5 - Equations of Lines and Planes - 12.5 Exercises - Page 832: 51

Answer

Perpendicular.

Work Step by Step

$x+4y-3=1$ and $-3x+6y+7z=0$ Since the dot product of the two vectors is equal to zero, they are perpendicular. $n_1=\lt1,4,-3\gt$ and $n_2=\lt -3,6,7\gt$ $n_1 \cdot n_2=\lt1,4,-3\gt \cdot \lt -3,6,7\gt$ $n_1 \cdot n_2=-3+24-21$ $n_1 \cdot n_2=0$ Hence, the planes are perpendicular.
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