Answer
$\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1$
Work Step by Step
Normal vector is: $\lt bc,ac,ab\gt$
The general form of the equation of the plane is:
$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$
or, $ax+by+cz=ax_0+by_0+cz_0$
Here, $n=\lt bc,ac,ab\gt$ and $r_0=(a,0,0)$
Thus,
$bc(x-a)+ac(y-0)+ab(z-0)=0$
$xbc+yac+zab=abc$
Divide throughout by $abc$ and we get
$\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1$
