Answer
Paraboloid
Work Step by Step
Rewrite as:
$x=y^2+z^2-2y-4z+5$
or, $x=(y^2-2y)+(z^2-4z)+5$
or, $x=(y^2-2y+1)+(z^2-4z+4)+5-1-4$
or, $x=(y-1)^2+(z-2)^2$
We find that this is a paraboloid with vertex $(0,1,2)$, which opens in the +x-axis direction.
