Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Review - Exercises - Page 843: 23

Answer

Skew

Work Step by Step

We will re-write the parametric equations as follows: $x=1+2t; y=2+3t; z=3+4t$ and $t=\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}$ $x=-1+6s; y=3-s; z=-5+2s$ and $s=\dfrac{x+1}{6}=\dfrac{y-3}{-1}=\dfrac{z+5}{2}$ Now, we will set the equations equal to each other. So, $s=\dfrac{2}{5}; t=-1+(3)(\dfrac{2}{5})=\dfrac{1}{5}$ Now, $3+(4) (\dfrac{1}{5})=-5+(2)(\dfrac{2}{5}) \implies \dfrac{19}{5} \ne -\dfrac{21}{5}$ This implies that the lines do not intersect, so they are skew.
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