Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Review - Exercises - Page 843: 30

Answer

Parabolic Cylinder

Work Step by Step

We have: $y=z^2$ This implies that there is no $x$ in the equation and the trace in the $x=0$ plane is a parabola, which is translated into the parallel planes x=k. Therefore, this is a Parabolic Cylinder that opens in the +y-axis direction.
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