Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Review - Exercises - Page 843: 15


$x=4-3t,y=-1+2t,z= 2+3t$

Work Step by Step

Given: $A(4,-1,2), B(1,1,5)$ The direction of the vectors is $\lt-3,2,3 \gt$ Formula for a line $r=r_{0}+tv$ where $r_{0}$ is the starting point vector and $v$ is the direction vector. $r=\lt 4,-1,2\gt+t \lt -3,2,3\gt$ Therefore, the parametric equations of the line are: $x=4-3t,y=-1+2t,z= 2+3t$
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