## Calculus: Early Transcendentals 8th Edition

$x=4-3t,y=-1+2t,z= 2+3t$
Given: $A(4,-1,2), B(1,1,5)$ The direction of the vectors is $\lt-3,2,3 \gt$ Formula for a line $r=r_{0}+tv$ where $r_{0}$ is the starting point vector and $v$ is the direction vector. $r=\lt 4,-1,2\gt+t \lt -3,2,3\gt$ Therefore, the parametric equations of the line are: $x=4-3t,y=-1+2t,z= 2+3t$