Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.2 - Areas and Lengths in Polar Coordinates - 10.4 Exercises - Page 673: 44

Answer

$ 204.16 m^{2}$

Work Step by Step

$y=4$ $rsin\theta=4$ $r=\frac{4}{sin\theta}$ $\frac{4}{sin\theta}=8+8sin\theta$ $\theta=arcsin\frac{-1+\sqrt 3}{2}$ $\approx 0.374734$ radians or $21.47 ^\circ $ $\theta=arcsin\frac{-1-\sqrt 3}{2}$ $=arcsin(-1.3660254)$ $A=2\int_{0.374734}^{\pi/2}(\frac{1}{2})((8+8sin\theta)^{2}-(\frac{4}{sin\theta})^{2}d\theta$ $=16[3\pi-(-3.33522)]$ $\approx 204.16 m^{2}$
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