Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.2 - Areas and Lengths in Polar Coordinates - 10.4 Exercises - Page 673: 19



Work Step by Step

$r=sin4\theta$ Area enclosed by one loop is $A=\int_{0}^{\pi/4}\frac{( {sin4\theta})^{2}}{2}d \theta$ $=\int_{0}^{\pi/4}\frac{( {1-cos8\theta})}{4}d \theta$ $=\frac{\pi}{16}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.