Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.1 - Curves Defined by Parametric Equations - 10.1 Exercises - Page 645: 18

Answer

$y^{2}=x+1$

Work Step by Step

a) $\tan^{2}\theta+1=\sec^{2}\theta$ $y^{2}=x+1$
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