Answer
a: $y=\frac{1}{x}$
b: See graph below
Work Step by Step
a: $x = sin(t), y = csc(t)= \frac{1}{sin(t)}$
We can either substitute $sin(t)$ with $x$, or use inverses to solve.
INVERSE:
$x = sin(t) $
$arcsin(x)=t$
$y= \frac{1}{sin(t)} = \frac{1}{sin(arcsin(x))}=\frac{1}{x}$
b:
