Answer
$y=e^{-2\ln\left(x\right)}=e^{\ln\left(x^{-2}\right)}=x^{-2}={\frac{1}{x^{2}}}$
Work Step by Step
a)
$\ln(x)=t$
$y=e^{-2\ln\left(x\right)}=e^{\ln\left(x^{-2}\right)}=x^{-2}={\frac{1}{x^{2}}}$
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