Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.1 - Curves Defined by Parametric Equations - 10.1 Exercises - Page 645: 11

Answer

a: $sin(\frac{θ}{2})^{2}+cos(\frac{θ}{2})^{2}=1$ b: See graph below

Work Step by Step

a: We first see that the graph is in terms of sne and cosine, so we can rewrite the function as $x^{2}+y^{2}=1$, with $sin(\frac{θ}{2}) = x,$ and $cos(\frac{θ}{2}) = y,. $sin(\frac{θ}{2})^{2}+cos(\frac{θ}{2})^{2}=1$
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