Answer
$ sin(\pi-x)= sin x$
Work Step by Step
Need to prove $ sin({\pi}-x)=sinx$
$sin(A-B)=sinA cos B-cos A sin B$
Thus,
$ sin(\pi-x)=sin\pi cos x-cos \pi sin x$
$ sin(\pi-x)=0*cos x-(-1) sin x$
Hence, $ sin(\pi-x)= sin x$
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