Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 32: 44


$ sin(\pi-x)= sin x$

Work Step by Step

Need to prove $ sin({\pi}-x)=sinx$ $sin(A-B)=sinA cos B-cos A sin B$ Thus, $ sin(\pi-x)=sin\pi cos x-cos \pi sin x$ $ sin(\pi-x)=0*cos x-(-1) sin x$ Hence, $ sin(\pi-x)= sin x$
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