Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 32: 25

Answer

$sin\frac{9\pi}{2}=1$ $cos\frac{9\pi}{2}=0$ $tan\frac{9\pi}{2}= undefined$ $csc\frac{9\pi}{2}=1$ $sec\frac{9\pi}{2}=undefined$ $cot\frac{9\pi}{2}=0$

Work Step by Step

The trigonometric ratios and their inverse trigonometric ratios are given as follows: $sin\frac{9\pi}{2}=sin\frac{\pi}{2}=1$ $cos\frac{9\pi}{2}=cos\frac{\pi}{2}=0$ $tan\frac{9\pi}{2}=tan\frac{\pi}{2} = undefined$ $csc\frac{9\pi}{2}=\frac{1}{sin\frac{9\pi}{2}}=1$ $sec\frac{9\pi}{2}=\frac{1}{cos\frac{9\pi}{2}}=undefined$ $cot\frac{9\pi}{2}=\frac{1}{tan\frac{9\pi}{2}}=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.