Answer
The equation for the circle that has Center (-2,-8) and radius 10 is:
$(x+2)^{2} + (y+8)^{2}= 100 $
Work Step by Step
Having the general equation of the circle we have:
$(x-h)^{2} + (y-k)^{2}= r^{2} $
We know that h is the displacement in the x axis and k is the displacement in the y axis. Then the equation for the circle that has Center (-2,-8) and radius 10 is:
$(x+2)^{2} + (y+8)^{2}= 100 $