Answer
$(x-3)^2 +(y+1)^2 = 25$
Work Step by Step
knowing the equation of the circle:
$(x-h)^2 + (y-k)^2 = r^2$
we say that:
$h= 3$
$k=-1$
$r=5$
then
$(x-3)^2 + (y+1)^2 = 5^2$
$(x-3)^2 + (y+1)^2 = 25$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
APPENDIX C - Graphs of Second-Degree Equations - C Exercises - Page A 23: 1
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