Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX C - Graphs of Second-Degree Equations - C Exercises - Page A 23: 16

Answer

$\frac{x^2}{4}+\frac{y^2}{25} = 1$ This is an equation of an ellipse.
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Work Step by Step

$25x^2+4y^2 = 100$ $\frac{x^2}{4}+\frac{y^2}{25} = 1$ We can write the general form of an ellipse: $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2} = 1$ The equation in the question is an equation of an ellipse, where $a = 2, b = 5, h = 0,$ and $k = 0$
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