## Calculus: Early Transcendentals 8th Edition

$\frac{x^2}{4}+\frac{y^2}{25} = 1$ This is an equation of an ellipse.
$25x^2+4y^2 = 100$ $\frac{x^2}{4}+\frac{y^2}{25} = 1$ We can write the general form of an ellipse: $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2} = 1$ The equation in the question is an equation of an ellipse, where $a = 2, b = 5, h = 0,$ and $k = 0$