Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 9 - Power Series - 9.2 Properties of Power Series - 9.2 Exercises - Page 683: 57

Answer

$\sum_{k=1}^{\infty} \dfrac{(-x^k)}{k+1}$

Work Step by Step

We are given the power series $1-\dfrac{x}{2}+\dfrac{x^2}{3}-\dfrac{x^3}{4}+...$ The given series can be represented in the summation form as: $1-\dfrac{x}{2}+\dfrac{x^2}{3}-\dfrac{x^3}{4}+...=\sum_{k=1}^{\infty} \dfrac{(-x^k)}{k+1}$
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