## Calculus: Early Transcendentals (2nd Edition)

a) $\{7.5, 1.875, 0.46875, 0.1171875\}$ b) $h_n = 0.25^n(30)$
a) $h_n = rh_{n-1}$ $h_1 = 0.25h_0 = 7.5$ $h_2 = 0.25h_1 = 1.875$ $h_3 = 0.25h_2 = 0.46875$ $h_4 = 0.25h_3 = 0.1171875$ b) We have to multiply the initial value $h_0$ by $r$, $n$ number of times. $h_n = r^nh_{0} = 0.25^n(30)$