Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises - Page 605: 40

Answer

$a_1 = -1$ $a_2 = -11$ $a_3 = -111$ $a_4 = -1111$ Diverges. The terms are decreasing without a bound.

Work Step by Step

$a_{n+1} = 10a_n -1$; $a_0 = 0$ $a_1 = 10(a_0)-1 = -1$ $a_2 = 10(a_1)-1 = -11$ $a_3 = 10(a_2)-1 = -111$ $a_4 = 10(a_3)-1 = -1111$ Diverges. The terms are decreasing without a bound.
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