Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises: 31

Answer

$a_1 = 9$ $a_2 = 99$ $a_3 = 999$ $a_4 = 9999$ Diverges. The terms increase without a bound as $n$ increases.

Work Step by Step

$a_n = 10^n - 1$ $a_1 = 10^1 - 1 = 9$ $a_2 = 10^2 - 1 = 99$ $a_3 = 10^3 - 1 = 999$ $a_4 = 10^4 -1 = 9999$ It diverges because the terms increase without a bound as $n$ increases.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.