## Calculus: Early Transcendentals (2nd Edition)

a) $14$ and $17$ b) $a_{n+1} = a_n + 3$, $a_1 = 2$ c) $a_n = -1 + 3n$
a) The next term is simply the previous term with three added to it. Thus, the next two terms are $14$ and $17$. b) The first term is $2$, thus $a_1 = 2$. Three is simply added to the previous term. $a_{n+1} = a_n + 3$ c) In order to get the $n$th term, we need to add three, $n$ number of times, to the initial value. $a_n = -1 + 3n$ We start with $-1$ so that our first term is $2$.