Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises - Page 605: 26


a) $14$ and $17$ b) $a_{n+1} = a_n + 3$, $a_1 = 2$ c) $a_n = -1 + 3n$

Work Step by Step

a) The next term is simply the previous term with three added to it. Thus, the next two terms are $14$ and $17$. b) The first term is $2$, thus $a_1 = 2$. Three is simply added to the previous term. $a_{n+1} = a_n + 3$ c) In order to get the $n$th term, we need to add three, $n$ number of times, to the initial value. $a_n = -1 + 3n$ We start with $-1$ so that our first term is $2$.
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