Answer
$0,2,15,679$
Work Step by Step
$a_{n+1} = 3_n^2 + n + 1$
$a_1 = 0$
To find the first four terms, we need to find $a_1, a_2, a_3$, and $a_4$.
$a_1 = 0$
$a_2 = 3(0)^2 + 1 + 1 = 2$
$a_3 = 3(2)^2 + 2 + 1 = 15$
$a_4 = 3(15)^2 + 3 + 1 = 679$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises - Page 604: 21
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