Answer
$10,18,42,114$
Work Step by Step
$a_{n+1} = 3a_n-12$
$a_1 = 10$
To find the first four terms, we need to find $a_1, a_2, a_3$, and $a_4$.
$a_1 = 10$
$a_2 = 3(10)-12 = 18$
$a_3 = 3(18)-12 = 42$
$a_4 = 3(42)-12 = 114$
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