#### Answer

$10,18,42,114$

#### Work Step by Step

$a_{n+1} = 3a_n-12$
$a_1 = 10$
To find the first four terms, we need to find $a_1, a_2, a_3$, and $a_4$.
$a_1 = 10$
$a_2 = 3(10)-12 = 18$
$a_3 = 3(18)-12 = 42$
$a_4 = 3(42)-12 = 114$

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

$10,18,42,114$

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