#### Answer

$0, 3, 10,21$

#### Work Step by Step

$a_n = 2n^2 - 3n + 1$
To find the first four terms, we need to find $a_1, a_2, a_3$, and $a_4$.
$a_1 = 2(1)^2 - 3(1) + 1 = 0$
$a_2 = 2(2)^2 - 3(2) + 1 = 3$
$a_3 = 2(3)^2 - 3(3) + 1 = 10$
$a_4 = 2(4)^2 - 3(4) + 1 = 21$