Answer
$$\frac{1}{x}{\text{ is not defined for }}x = 0$$
Work Step by Step
$$\eqalign{
& \int_{ - 1}^1 {\frac{{dx}}{x}} = \left[ {\ln \left| x \right|} \right]_{ - 1}^1 = \ln \left| 1 \right| - \ln \left| { - 1} \right| = 0 \cr
& {\text{This is wring because the integrand }}\frac{1}{x}{\text{ is not defined for }}x = 0 \cr
& {\text{which is in the interval }}\left[ { - 1,1} \right]. \cr} $$
