Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.8 Improper Integrals - 7.8 Exercises - Page 578: 4

Answer

$$p > 1$$

Work Step by Step

$$\eqalign{ & \int_1^\infty {{x^{ - p}}dx} = \frac{1}{{p - 1}}{\text{ if }}p > 1 \cr & {\text{The integral converges if }}p > 1 \cr & {\text{The integral diverges if }}p \leqslant 1 \cr} $$
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