Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.1 Basic Approaches - 7.1 Exercises - Page 514: 6


A good first step would be to take out a $\frac{1}{3}$ out of the integral and divide the Integrand's numerator by the denominator.

Work Step by Step

After taking out the $\frac{1}{3}$ and evaluating the Integrand, you get: $\int \frac{x^{10}-2x^4+10x^2+1}{3x^3 dx}$ = $\frac{1}{3} \int \frac{x^{10}-2x^4+10x^2+1}{x^3} dx$ = $\frac{1}{3} \int (x^7 -2x+\frac{10}{x}+\frac{1}{x^3})dx$, which is easier to integrate.
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