Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.1 Basic Approaches - 7.1 Exercises - Page 514: 3


The Trigonometric Identity $sin^2(x) dx = \frac{1-cos(2x)}{2}$ would be useful.

Work Step by Step

Using $sin^2(x)$ = $\frac{1-cos(2x)}{2}$, $\int sin^2(x) dx = \int \frac{1-cos(2x)}{2} dx$. This can be rewritten to be $\frac{1}{2} \int 1-cos(2x) dx$, which is easier to integrate.
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