Answer
$\int \frac{x+2}{x+4} dx$ = $x-2\ln|x+4| + C$
Work Step by Step
Using polynomial division, $\int \frac{x+2}{x+4} dx$ = $\int (1-\frac{2}{x+4} )dx$.
$\int (1-\frac{2}{x+4} )dx$ = $x-2\ln|x+4| + C$
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