Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.1 Basic Approaches - 7.1 Exercises - Page 514: 29

Answer

$\int \frac{x+2}{x+4} dx$ = $x-2\ln|x+4| + C$

Work Step by Step

Using polynomial division, $\int \frac{x+2}{x+4} dx$ = $\int (1-\frac{2}{x+4} )dx$. $\int (1-\frac{2}{x+4} )dx$ = $x-2\ln|x+4| + C$
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