## Calculus: Early Transcendentals (2nd Edition)

$\int \frac{x+2}{x+4} dx$ = $x-2\ln|x+4| + C$
Using polynomial division, $\int \frac{x+2}{x+4} dx$ = $\int (1-\frac{2}{x+4} )dx$. $\int (1-\frac{2}{x+4} )dx$ = $x-2\ln|x+4| + C$