Answer
$${\text{The first step in the integrating }}\frac{{10}}{{{x^2} - 4x + 5}}{\text{ is factor the denominator }}$$
Work Step by Step
$$\eqalign{
& \int {\frac{{10}}{{{x^2} - 4x + 5}}} dx \cr
& {\text{The first step in the integrating }}\frac{{10}}{{{x^2} - 4x + 5}}{\text{ is factor the denominator }} \cr
& {x^2} - 4x + 5{\text{ that way it is posible decompose it into partial fractions}}{\text{.}} \cr} $$
