Answer
$\dfrac {9}{4}=2.25$
Work Step by Step
$\lim _{t\rightarrow 2}\dfrac {t^{2}+5}{1+\sqrt {t^{2}+5}}=\dfrac {2^{2}+5}{1+\sqrt {2^{2}+5}}=\dfrac {9}{1+\sqrt {9}}=\dfrac {9}{4}=2.25$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 109: 50
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