Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 109: 50


$\dfrac {9}{4}=2.25$

Work Step by Step

$\lim _{t\rightarrow 2}\dfrac {t^{2}+5}{1+\sqrt {t^{2}+5}}=\dfrac {2^{2}+5}{1+\sqrt {2^{2}+5}}=\dfrac {9}{1+\sqrt {9}}=\dfrac {9}{4}=2.25$
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