Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 109: 29



Work Step by Step

$\lim _{x\rightarrow 1}\left( \dfrac {x+5}{x+2}\right) ^{4}=\left( \dfrac {1+5}{1+2}\right) ^{4}=\left( \dfrac {6}{3}\right) ^{4}=2^{4}=16$
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