Answer
$-5$
Work Step by Step
$\lim _{x\rightarrow -1}\left( x^{2}-4+\sqrt [3] {x^{2}-9}\right) =\left( -1\right) ^{2}-4+\sqrt [3] {\left( -1\right) ^{2}-9}=-3+\sqrt [3] {-8}=-3+\left( -2\right) =-5$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 109: 48
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