Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 109: 48



Work Step by Step

$\lim _{x\rightarrow -1}\left( x^{2}-4+\sqrt [3] {x^{2}-9}\right) =\left( -1\right) ^{2}-4+\sqrt [3] {\left( -1\right) ^{2}-9}=-3+\sqrt [3] {-8}=-3+\left( -2\right) =-5$
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