Answer
$\dfrac {81}{16}=5.0625$
Work Step by Step
$\lim _{x\rightarrow 2}\left( \dfrac {3}{2x^{5}-4x^{2}-50}\right) ^{4}=\left( \dfrac {3}{2\times 2^{5}-4\times 2^{2}-50}\right) ^{4}=\left( \dfrac {3}{2\times 32-4\times 4-50}\right) ^{4}=\left( \dfrac {3}{64-16-50}\right) ^{4}=\left( \dfrac {-3}{2}\right) ^{4}=\dfrac {81}{16}$
