## Calculus: Early Transcendentals (2nd Edition)

$\lim\limits_{x\to 1}$ $\frac{x-1}{\sqrt x-1}$ = $\lim\limits_{x\to 1}$ $\frac{(\sqrt x-1)(\sqrt x+1)}{\sqrt x-1}$ = $\lim\limits_{x\to 1}$ $\sqrt x+1$ = $\sqrt 1$+1 =2