Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 70

Answer

$80$

Work Step by Step

$\lim _{x\rightarrow 2}\dfrac {x^{5}-32}{x-2}=\lim _{x\rightarrow 2}\dfrac {\left( x-2\right) \left( x^{4}+x^{3}\times 2+x^{2}2^{2}+x\times 2^{3}+2^{4}\right) }{\left( x-2\right) }=x^{4}+2x^{3}+4x^{2}+8x+16=16+16+16+16+16=80$
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