Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 78: 60



Work Step by Step

$\lim _{h\rightarrow 0}\dfrac {100}{\left( 10h-1\right) ^{11}+2}=\dfrac {100}{\left( 10\times 0-1\right) ^{11}+2}=\dfrac {100}{\left( -1\right) ^{11}+2}=\dfrac {100}{-1+2}=100$
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