Answer
$10$
Work Step by Step
$\lim _{h\rightarrow 0}\dfrac {\left( 5+h\right) ^{2}-25}{h}=\dfrac {25+10h+h^{2}-25}{h}=\dfrac {10h+h^{2}}{h}=\dfrac {h\left( 10+h\right) }{h}=10+h=10+0=10$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 78: 65
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