Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 76: 24

Answer

$$3$$

Work Step by Step

$Assume \lim\limits_{x \to 1} f(x) = 8, \lim\limits_{x \to 1 } g(x) = 3$ $\lim\limits_{x \to 1}$ $\sqrt[3] {f(x)g(x)+3}$ =$(\lim\limits_{x \to 1} f(x)*\lim\limits_{x \to 1}g(x)+\lim\limits_{x \to 1} 3)^{1/3}$ =$(8*3+3)^{1/3}$ =$(24+3)^{1/3}$ =$(27)^{1/3}$ =$3$
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