Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 76: 23



Work Step by Step

Given $$\lim\limits_{x \to 1} h(x)=2$$ Therefore, we have $$\lim\limits_{x \to 1} {(h(x))}^5={(\lim\limits_{x \to 1} h(x))}^5={(2)}^5=32$$
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