Answer
32
Work Step by Step
Given $$\lim\limits_{x \to 1} h(x)=2$$
Therefore, we have
$$\lim\limits_{x \to 1} {(h(x))}^5={(\lim\limits_{x \to 1} h(x))}^5={(2)}^5=32$$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 76: 23
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