Answer
$\lim\limits_{x \to 1}{(-2x+5)}=3$
Work Step by Step
$lets$ $choose$ $f(x)=-2x+5$
$\lim\limits_{x \to 1}{(-2x+5)}=\lim\limits_{x \to 1}{f(x)}$
when $f(x)=-2x+5$
$\lim\limits_{x \to 1}{f(x)}=f(1)=-2\times1+5=-2+5=3$
Therefore
$\lim\limits_{x \to 1}{(-2x+5)}=3$
