Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 76: 12


$\lim\limits_{x \to 1}{(-2x+5)}=3$

Work Step by Step

$lets$ $choose$ $f(x)=-2x+5$ $\lim\limits_{x \to 1}{(-2x+5)}=\lim\limits_{x \to 1}{f(x)}$ when $f(x)=-2x+5$ $\lim\limits_{x \to 1}{f(x)}=f(1)=-2\times1+5=-2+5=3$ Therefore $\lim\limits_{x \to 1}{(-2x+5)}=3$
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