Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 13 - Multiple Integration - 13.2 Double Integrals over General Regions - 13.2 Exercises - Page 981: 32

Answer

\[\int_{-4}^{5}{\int_{-y/3+5/3}^{\sqrt{25-{{y}^{2}}}}f(x,y) {dx}dy}\]

Work Step by Step

\[\begin{align} & x=\sqrt{25-{{y}^{2}}} \\ & y=-3x+5\to x=-\frac{1}{3}y+\frac{5}{3} \\ & \text{From the graph, the region }R\text{ is} \\ & R=\left\{ \left( x,y \right):-\frac{1}{3}y+\frac{5}{3}\le x\le \sqrt{25-{{y}^{2}}},\text{ }-4\le y\le 5 \right\} \\ & \text{Then,} \\ & \int_{-4}^{5}{\int_{-y/3+5/3}^{\sqrt{25-{{y}^{2}}}}f(x,y) {dx}dy} \\ \end{align}\]
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