Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 13 - Multiple Integration - 13.2 Double Integrals over General Regions - 13.2 Exercises - Page 981: 13

Answer

\[\int_{0}^{1}{\int_{0}^{-2x+2}{f\left( x,y \right)}}dydx\]

Work Step by Step

\[\begin{align} & \text{The region }R\text{ is represented in the graph shown below} \\ & R=\left\{ \left( x,y \right):0\le y\le -2x+2,\text{ }0\le x\le 1 \right\} \\ & \text{Then,} \\ & \iint_{R}{f\left( x,y \right)}dA=\int_{0}^{1}{\int_{0}^{-2x+2}{f\left( x,y \right)}}dydx \\ \end{align}\]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.