Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 13 - Multiple Integration - 13.2 Double Integrals over General Regions - 13.2 Exercises - Page 981: 31

Answer

\[\int_{0}^{18}{\int_{y/2}^{y/3+3}f(x,y) {dx}dy}\]

Work Step by Step

\[\begin{align} & y=2x\to x=\frac{1}{2}y \\ & y=3x-9\to x=\frac{1}{3}y+3 \\ & \text{From the graph, the region }R\text{ is} \\ & R=\left\{ \left( x,y \right):\frac{1}{2}y\le x\le \frac{1}{3}y+3,\text{ }0\le y\le 18 \right\} \\ & \text{Then,} \\ & \int_{0}^{18}{\int_{y/2}^{y/3+3}f(x,y) {dx}dy} \\ \end{align}\]
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