Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.6 Calculus of Vector-Valued Functions - 11.6 Exercises: 41

Answer

$\textbf{r}''(t) = \langle 2, 0 , 0\rangle$ $\textbf{r}'''(t) = \langle 0, 0, 0\rangle$

Work Step by Step

To find the derivative, simply find the derivative of each component. $\textbf{r}(t) = \langle t^2+1, t+1 , 1\rangle$ $\textbf{r}'(t) = \langle 2t, 1 , 0\rangle$ $\textbf{r}''(t) = \langle 2, 0 , 0\rangle$ $\textbf{r}'''(t) = \langle 0, 0, 0\rangle$
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