Answer
$\textbf{r}'(ln(3)) = \langle 6, \frac{-2}{9}, 72\rangle$
Work Step by Step
$\textbf{r}(t) = \langle f(t), g(t), h(t)\rangle$
$\textbf{r}'(t) = \langle f'(t), g'(t), h'(t)\rangle$
$\textbf{r}(t) = \langle 2e^t, e^{-2t}, 4t^{2t}\rangle$
$\textbf{r}'(t) = \langle 2e^t, -2e^{-2t}, 8t^{2t}\rangle$
$\textbf{r}'(ln(3)) = \langle 2e^{ln(3)}, -2e^{-2ln(3)}, 8t^{2ln(3)}\rangle = \langle 6, \frac{-2}{9}, 72\rangle$