Chapter 11 - Vectors and Vector-Valued Functions - 11.6 Calculus of Vector-Valued Functions - 11.6 Exercises - Page 815: 22

$\textbf{T}(t) = \langle -sin(t), cos(t), 0\rangle$

$\textbf{r}(t) = \langle f(t), g(t), h(t)\rangle$ $\textbf{r}'(t) = \langle f'(t), g'(t), h'(t)\rangle$ $\textbf{r}(t) = \langle cos(t), sin(t), 2\rangle$ $\textbf{r}'(t) = \langle -sin(t), cos(t), 0\rangle$ $|\textbf{r}'(t)| = \sqrt {(-sin(t))^2 + (cos(t))^2 + (0)^2} = \sqrt {1} = 1$ $\textbf{T}(t) = \frac{\textbf{r}'(t)}{|\textbf{r}'(t)|} = \frac{\langle -sin(t), cos(t), 0\rangle}{1} = \langle -sin(t), cos(t), 0\rangle$