Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 769: 66

Answer

$x=\left(-\dfrac{17}{2},\dfrac{11}{4}\right)$

Work Step by Step

We are given: $x=(a,b)$ $u=(2,-3)$ $v=(-4,1)$ $-4x=u-8v$ Substitute the expressions of the vectors in the equation: $-4(a,b)=(2,-3)-8(-4,1)$ $(-4a,-4b)=(2,-3)-(-32,8)$ $(-4a,-4b)=(2+32,-3-8)$ $(-4a,-4b)=(34,-11)$ Determine $a,b$: $\begin{cases} -4a=34\\ -4b=-11 \end{cases}$ $a=-\dfrac{34}{4}=-\dfrac{17}{2}$\\ $b=\dfrac{-11}{-4}=\dfrac{11}{4}$ The solution is: $x=\left(-\dfrac{17}{2},\dfrac{11}{4}\right)$
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