Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 769: 63

Answer

$x=\left(\dfrac{1}{5},-\dfrac{3}{10}\right)$

Work Step by Step

We are given: $x=(a,b)$ $u=(2,-3)$ $v=(-4,1)$ $10x=u$ Substitute the expressions of the vectors in the equation: $10(a,b)=(2,-3)$ $(10a,10b)=(2,-3)$ Determine $a,b$: $\begin{cases} 10a=2\\ 10b=-3 \end{cases}$ $a=\dfrac{2}{10}=\dfrac{1}{5}$ $b=-\dfrac{3}{10}$ The solution is: $x=\left(\dfrac{1}{5},-\dfrac{3}{10}\right)$
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